x^2+(x/4)=1/32

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Solution for x^2+(x/4)=1/32 equation: 


x in (-oo:+oo)

x^2+x/4 = 1/32 // - 1/32

x^2+x/4-(1/32) = 0

x^2+x/4-1/32 = 0

x^2+1/4*x-1/32 = 0

DELTA = (1/4)^2-(-1/32*1*4)

DELTA = 3/16

DELTA > 0

x = ((3/16)^(1/2)-1/4)/(1*2) or x = (-(3/16)^(1/2)-1/4)/(1*2)

x = ((3/16)^(1/2)-1/4)/2 or x = (-((3/16)^(1/2)+1/4))/2

x in { (-((3/16)^(1/2)+1/4))/2, ((3/16)^(1/2)-1/4)/2 }

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